بسته بندی مجدد در تکلیف متغیر پایتون

v1, v2, v3 = [0, 1, 2]
v1, v2, v3 = 0, 1, 2 # Tuple
v1, v2, v3 = (0, 1, 2)
# No error

v1, v2, v3 = [0, 1]
# ValueError: not enough values to unpack (expected 3, got 2)

v1, v2, v3 = [0, 1, 2, 3]
# ValueError: too many values to unpack (expected 3)

v1 = [0, 1, 2]
# No error

v1, = [0, 1, 2]
# ValueError: too many values to unpack (expected 1)

v1, = [5]
v1, = 5, # Tuple
v1, = (5,)

v1, = 5
# TypeError: cannot unpack non-iterable int object

v1, = [5, 10]
# ValueError: too many values to unpack (expected 1)

v1, = []
# ValueError: not enough values to unpack (expected 1, got 0)

, = []
# SyntaxError: invalid syntax

_, = []
# ValueError: not enough values to unpack (expected 1, got 0)

v1, v2, v3 = [0, 1, 2]
v1, v2, v3 = 0, 1, 2 # Tuple
v1, v2, v3 = (0, 1, 2)
v1, v2, v3 = range(3)

print(v1, v2, v3) # 0 1 2

v1 = [0, 1, 2]

print(v1) # [0, 1, 2]

v1, = [5]
v1, = 5, # Tuple
v1, = (5,)
v1, = range(5, 6)

print(v1) 5

v1, v2, v3 = {"name":"John", "age":36, "gender":"Male"}
v1, v2, v3 = {"name":"John", "age":36, "gender":"Male"}.keys()

print(v1, v2, v3) # name age gender

v1, v2, v3 = {"name":"John", "age":36, "gender":"Male"}.values()

print(v1, v2, v3) # John 36 Male

v1, v2, v3 = {"name":"John", "age":36, "gender":"Male"}.items()

print(v1, v2, v3)
# ('name', 'John') ('age', 36) ('gender', 'Male')

print(v1[0], v1[1], v2[0], v2[1], v3[0], v3[1])
# name John age 36 gender Male

v1, v2, v3, v4, v5 = "Hello"

print(v1, v2, v3, v4, v5) # H e l l o