چالش نام و نام خانوادگی

[whole | first <- ["Eva", "Mike"],
         last <- ["Smith", "Wood", "Odd"],
         let whole = first ++ last,
         even (length whole)]

require Integer

for first <- ~w[Eva Mike],
  last <- ~w[Smith Wood Odd],
  name <- [first <> last],
  name
  |> String.length()
  |> Integer.is_even(), do: name

const nombres = ["Eva", "Mike"];
const apellidos = ["Smith", "Wood", "Odd"];

const output = [];

for(let i = 0; i < nombres.length; i++){
    for(let j = 0; j < apellidos.length; j++){
        const fullName = `${nombres[i]}${apellidos[j]}`;
        if(fullName.length % 2 == 0){
            output.push(fullName);
        }
    }
}

const nombres = ["Eva", "Mike"];
const apellidos = ["Smith", "Wood", "Odd"];

const output = nombres.flatMap(n =>
        apellidos.map(a => `${n}${a}`)
    )
    .filter(fullName => fullName.length % 2 == 0);

~w[Eva Mike]
|> Enum.flat_map(fn first ->
  ~w[Smith Wood Odd]
  |> Enum.map(fn last ->
    first <> last
  end)
end)
|> Enum.filter(&
    &1
    |> String.length()
    |> Integer.is_even()
)